//鸡兔同笼问题
//某车棚存有自行车和三轮车共65辆,他们的轮子合计为150个。
//需求:求该车棚内存的自行车和三轮车分别多少?
#include <iostream>
using namespace std;
int main()
{
int a = 65;
int b = 150;
int bike, sanlun;
sanlun = b - a * 2;
bike = a - sanlun;
cout << "自行车数量为:" << bike << endl;
cout << "三轮车数量为:" << sanlun << endl;
}
© 版权声明
THE END
暂无评论内容